* **Giza Complex Rectangle*

*As indicated within the additional Giza Blueprint essays, I calculated the three Giza Pyramids enclosed within a “rectangle” of lengths*

*North to South**: **2976.278125** **feet…………**East to West**: **2435.778125** **feet*

*The musical scale, Pythagorean Limma {256:243} denoted as FP { Fraction of Plato} since it is utilized within the Dialogues of Plato: Timaeus with regard to the creation of the “World-Soul” The Egyptian cubit of 1.71818, the square feet in one acre: 43560, the seconds in 24 hours: 86400*

*North to South**: **2976.278125** **÷ 1.7 1818 = 1732.22536375661*

*East to West* *2435.778125** **÷ 1.7 1818 = 1417.64864417989*

*Likewise √3 x 1000 = 1732.0508075688…and*

**√2**, x 1000 = 1414.213562373095... therefore it would be a simple matter of “fiddling” the measurements to obtain far more precise figures, however there is no “fiddling” within this website, the “numbers” speak for themselves*To Continue: *

*The 1732.22536 375661 x 273030912 = 472951070856, this is 43560 x 10857462.6 this is 435.978240966796875 x 24903.68… a tolerable Earth Equatorial circumference The 435.978240966796875 x 86400 x FP ÷ 2976.278125 = 13333.333 this is one third of 40000. *

*The 1417.64864 417989 x 273030912 = 387061902216 this is 43560 x 8885718.6 this is 356.803436279296875 x 24903.68… as prior The 356.803436279296875 x 86400 x FP ÷ 2435.778125 = 13333.333 as prior *

*The 273030912 is the GP Gallery unit: 1881 x 145152 the shorter value Roman cubit is 1.45152 The 273030912 is the GP base perimeter of 3024 x 90288 which is the British Admiralty: {Or as I dub it} : “Sea” mile of 6080 x 14.85 this multiplied by 16000 = 237600 this is the NC { Numerical Canon} mean distance Earth to Moon*

* **Earth year, Equatorial circumference, √2, the √3,*

*a “cubit” of approx: 20.6 etc*

*The North to South: 2976.278125 x √2 ÷ 204.12 = 20.62067847… a “cubit”, the 204.12 x 948.148148… = 193536 which is 64 x 3024, the 948.148148… is 900 times the Pythagorean Limma {256:243} the 20.62067847…÷ 12 x 440 = 756.0915439…*

*The **East to West**: 2435.778125 x √3 ÷ 204.8 = 20.60005599…a “cubit”, the 204.8 is 194.4 times the Pythagorean Limma {256:243} 2048 16th PWS member and 1944 is the 15th
*

*The** North to South**: **2976.278125** **÷ 1.7 1818 ÷ 1000 *

*= 1.732225363756… which is the*

**√3.0006047108**…accordingly 1.732225363756… is in the neighbourhood with reference to**√3**However 2976.278125 ÷**√3**÷ 1062 = 1.61803…A tolerable**Phi***East to West**: **2435.778125** **÷ 1.7 1818 ÷ 1000 = *

*1.41764864*

__417989__*which is the square root of*

**2.00972767**…accordingly*1.41764864*

__417989__*is close to*

**√2***However 2435.778125÷*

**√2**÷ 1064.474 = 1.61803… A tolerable**Phi.**Therefore all that needs be is to revisit to the measurements subsequently “adjust” them to suit the desired product, which I will, under no circumstances, actually carry out, in view of the fact that the “numbers” are as they are*As per norm: Gematria values denoted as**: **Gem*

*The 1st Pyramid {Great Pyramid} base perimeter of: 3024 x 5280 x *

*17.1*

*=*

*273030912*

*The **17.1** x 355. 555 = 6080, the “Sea” mile, the 355.555 x 0.54 = 192, this is Gem: Mary*

*In that case 6080 ÷*

**192**= 31.__666__the 31.__666__x 166.__73__= 5280 the British “Land” mile The 166.**684**2105263157894__73__x 19 =**684**2**105263**157894**3168**which is Gem: Lord Jesus Christ, otherwise**3168**÷ 0.6 = 5280*The 166. 736842105263157894 divided by the Greek cubit of 1.52064 afterwards multiplied by exactly *

*2490041.91744*

*will regain the*

*273030912*

*The*

*2490041.91744*

*, obviously 100 x*

*24900.4191744…*

*a tolerable Earth Equatorial circumference that multiplied by 5280 ÷ 360000 = 365.2061478912…not quite accurate, nonetheless a tolerable Earth year*

*The prior “near miss” √3 of *

*1.732225363756*

*…*

*x*

*273030912*

*=*

*472951070.856*

*The prior “near miss” √2 of *

*1.41764864*

__417989__*x*

*273030912*

*=*

*387061902.216*

*The GP course “number”:*

**203**÷ 3.5 =

*58**that multiplied by 28 = 1624 that plus a Colel {*

**1**} obtains:**1625**Gem: Tree of Life*The NC {*

**N**umerical**C**anon} Earth mean of 24883.2 reduced to 2.48832 x 17.1 =**42.550272***The*

**√3**x**√2**x**58**= 142.0704050814…*The prior **472951070.856** ÷ **142.0704050814** …÷ **Pi** ÷ **42.550272** = 24903.499589449 … that multiplied by 5280 ÷ 360000 = 365.2513273…*

*The Sea mile of 6080 ÷ **17.1** x 0.190170 4545 = *

*67.*

__61__61*subsequently*

*Phi**x*

*67.*

__61__61*÷*

*Pi**=*

*34.8247719381…*

*The prior*

*387061902.216*

*÷*

*142.0704050814*

*… ÷*

*Pi**÷*

*34.8247719381*

*… = 24902.253749689…that multiplied by 5280 ÷ 360000 = 365.23305499…*

*Within the foregoing we observe tolerable approximations regarding an Earth year with tolerable Earth Equatorial circumference’s, the 1st {Great Pyramid} base side length is 756 modern-day feet {please note the below 7.56015352710857…: } *

* **The 1st Pyramid denoted as GP*

*√2 x √3** ÷ 0.324 = 7.56015352710857… Denoted as W*

*Then 0.324 x 2333.333 = 756 the GP base side length, the 2333.333 x 3 = 7000 *

*The*

**0.324**x 1481.__481__481 = 480, the GP height 1481.__481__481 x*0.5103*

*= 756*

*The*

*0.5103*

*x 1120000 = 571536, the GP base area: 756 x 756*

*the*

**0.324**obtains: 729, 1296, 2592, 2916, 10368, etc**{1} ****W** x 1200 = *9072.18423253…tolerable as the GP 9072
*

**{2}** **W** x 761.__904761__ = *5760.11697303…tolerable as the GP 5760
*

**{3}** the *761. 904761*

*x 0.567 = 432, t*

*he*

*761.*

__904761__*divided by the FP {Musical Scale:*

*Pythagorean Limma*

*256:243} obtains: 723.2*

__142857__that multiplied by 4.48 =**3240***the 4.48 x*

**168.75**= 756 the GP base side length**{4}** the *761. 904761*

*÷*

*241.0*

__714285__*= 3.*

__160493827__this is the*Rhind Papyrus*

*fraction {256:81}*

*The 761.*

__904761__is 773.9984**882**84202… x 0.984375 this is the Eye of Horus fraction as: {63:64} the 773.9984**882**84202…x**0.97674609375**= 756 the GP base side length.*Within the 773.9984 88284202… we espy: 882 Gem: City of god, Hence: 882 ÷ 773.998488284202…= 1.139537109375 this is the 0.97674609375 x 1.1666 that multiplied by 144.6428571 = 168.75 within {3} and the 144.6428571 x 34.8444 = 5040*

*The “number” of most importance within the idealistic: City-State: Magnesia as envisioned via Plato, all of Magnesia must employ the usage of the number 5040, the number of Citizens, plots of land, in fact everything. The 34.8444 x 33.75 = 1176 Gem: Only-begotten son, which is 882 x 1.333 one third of 4, the {3} 723.2142857 is the {4} 144.6428571 x 5*

*The **0.97674609375** x **1053.4979423868**…= 1029 pertaining to the **Kermario Menhirs** Furthermore 1029 is 7 x 147 that multiplied by 5. 142857 = 756 The 5.142857 x 7 = 36, accordingly 5.142857 x 93.333 = 480, the 93.333 x 0.075 = 7 *

*The*

*1053.4979423868*

*… is one thousand times the FP {256:243}*

**{5}** the **{4}** *241.0 714285*

*divided by the Schooldays Pi {22:7} of 3.*

__142857__= 76.70__45__45 which is 66.96__428571__Egyptian feet of 1.1__45__45*The 66.96*

__428571__is 39.0625 x 1.__714285__{12 ÷ 7}, the 39.0625 x 256 = 10000*The {2} *

*5760.11697303*

*…÷*

**√2 ÷ √3**=*2351.557907113*

*…*

*The GP as 756 and 480 will obtain the Tan: 480 ÷ 378 =*

*1.*

__269841__*The*

*2351.557907113*

*…x 378 = 888888.*

__888__which is one ninth of 8000000*The*

*2351.557907113*

*…÷*

*1.*

__269841__*= 1851.*

__851__851 this is 1562.5 x 1.__185__185 the*Pythagorean Minor Third*

*{32:27}*

*Otherwise 1851.*

__851__851 x 54 = 100000, in addition to the 1562.5 x 64 = 100000*As indicated, I calculated the Three Giza Pyramids enclosed within a “rectangle” of distance*

*North **to South: **2976.278125** **feet*

*East **to West: **2435.778125 **feet*

*The North to South: **2976.278125** **x **3703. 703703*

*= 11023252.3*

__148__148 that multiplied by 243 =**2678650312.5**this divided by 189843.75 then divided by**√2 ÷ √3**=*5760.2866084799…*

*that multiplied by 1.575 =*

*9072.45140835…*

*Two additional acceptable approximations with reference to 9072 and 5760, the*

*3703.*

__703__703*x 243 = 900000*

*As a result, noticeably, the **5760.2866084799…** ÷ √2 ÷ √3 = 2351.6271604938… this divided by the *

*Rhind Papyrus*

*{256:81} of 3.*

__160493827__= 744.06953125 this is exactly one fourth of*2*

*976.278125*

**North**to**South***The*

*9072.45140835*

*…÷*

**√2 ÷ √3**= 3703.812__777__this is exactly:*2083.3946875*

*x 1.*

__777__which is the square root of the*Rhind Papyrus*

*{256:81} of 3.*

__160493827__*The prior*

**2678650312.5**÷*2083.3946875*

*= 1285714.*

__285714__which is one seventh of 9000000*As indicated prior: the **3703. 703703*

*x 243 = 900000*

And as prior: “*√2 x √3** ÷ 0.324 = 7.56015352710857… Denoted as W*…”

**{1}** **W** x 1200 = *9072.1842325302… **this divided by the** **3703. 703703*

*= 2.4494897427831… obviously:*

**√2 x √3****{2} ****W** x *761. 904761*

*=*

*5760.11697303*

*…*

*this divided by the*

*3703.*

__703__703*= 1.555231582719… this divided by divided by*

**√2 ÷ √3**=

*0.*__634920__

**this multiplied by**

*0.93555**=*

*0.594.*

*The*

*0.594*

*obtains: 237600, 1140480, 152064, 432432, etc the*

*0.93555**is, for example: 1.215 x*

**0.77***East **to West: **2435.778125 **feet*

**{1}** **W **x 1200 = *9072.1842325302…** that divided by the East to West **2435.778125** then multiplied by **1546.57133883541 666*

*=*

*5760.2866084799…*

*This*

*as per norm, multiplied by 1.575 =*

*9072.4514083559…*

*Two more satisfactory options with regard to*

*9072*

*and*

*5760*

*Likewise the **5760.2866084799…** is 3703.812 777 x 1.555231582719… that divided by *

*0.*__634920__*will regain the*

**√2 x √3,**{we observed

*0.*__634920__*previous}*

*The employed **1546.57133883541 666*

*x 9072 = 14030495.1859149 this is the North to South*

*2976.278125*

*x*

*4714.107552 that divided by the East to West:*

*2435.778125*

*will obtain exactly*

*1.93536 t*

*his*

*divided by the prior*

*0.93555**=*

*2.0*

__68__68*that multiplied by 1.5625 =*

*3.*

__23__23*that multiplied by 1881 = 6080, the Sea mile, and the 1.5625 x 256 = 400*

*Gem Mary: 192 ÷ *

*2.0*

__68__68*= 92.8125 that multiplied by 2560 = 237600 the NC {*

**N**umerical**C**anon} Earth to Moon distance*We may perhaps employ this*

*2.0*

__68__68*as a “cubit” given that 2.0*

__68__68 x 10 ÷ 12 =*1.*

__723905__*this multiplied by the mile of 5280 =*

**9102.**that divided by 9072 = 1.0033313737017… a tolerable Earth Equatorial and Polar circumference ratio In view of the fact that an Equatorial circumference of exactly 24902 ÷ 1.0033313737017…= 24819.317578125 a smidgen over the Intermediate circumference__222__*In addition to this **24819.317578125** plus **63.882421875** = 24883.2 the NC Earth mean circumference** This exact 63.882421875 x 256 = 16353.9 which is exactly 16299.6 x 1.00333137009…that multiplied by the 24819.317578125 = 24901.9999104…another, improved, Earth Equatorial circumference **The **16299.6** divided by the prior **1. 723905*

*will obtain exactly 9455.04140625 that is*

*312.850634765625*

*x*

*30.*

__222__*The **312.850634765625** x 256 x 256 = 20502979.2 which is the GP base side length of 9072 x 2260.0 285714 this is *

*1318.35*

*x 1.*

__714285__{12 ÷ 7}*the 1318.35 divided by the 1.*

__723905__= 764.74599609375 that divided by the 312.850634765625 = 2.__444__which is one ninth of 22*Likewise the*

**9102.**minus 9072 =__222__*30.*

__222__

__,__*this pertains to the*

*Alexander Thom Megalithic Yard*

*{*

*2.72**} seeing as*

*30.*

__222__*x 9 =*

*272**North **to South: **2976.278125** **feet*

*East **to West: **2435.778125 **feet*

*Yet again: √2 x √3 ÷ 0.324 = 7.5601535271085743… denoted as: W*

**{2}** **W** x *761. 904761*

*=*

*5760.1169730351*

*…x*

*2435.778125*

*=*

*14030366.9203601*

*21… this divided by*

**√2 ÷ √3**x 378 = 2165136111.__111__, one ninth of*19486225000*

*this*

*divided by the square feet in once acre: 43560 then divided by 1881 then multiplied by the Sea mile of 6080 = 138396.484375*

*This 138396.484375 divided by the East to West **2435.778125** **= **56. 8181*

*that multiplied by 52.382495 will obtain the*

*2976.278125*

*North*

*to South*

*The yards in one mile: 1760 x*

*56.*

__81__81*= 100000*

*the 14030366.920360121…÷ 11023252.3*

__148__148 = 1.272797403131…*The 11023252.3 148148 is 192862.8225 x 57.155921353452217… the square root of this is W, {7.5601535271085743… } Likewise as we have observed prior… “Yet again: √2 x √3 ÷ 0.324 = 7.5601535271085743… denoted as: W”…*

*The 11023252.3 148148 x 243 = 2678650312.5*

*, this is 900000 x 2976.278125*

**:**North to South*The {2} *

*5760.1169730351…*

*x*

*1.57496801583…*

*= 9072*

*then*

**W**÷ 1.57496801583…x 1200 = 5760.233948…that multiplied by 1.57493603232 = 9072*Exactly:** **1052256150 ÷ 567 = 1855830. 952380 x W = *

*14030366.920360121…*

*The ratio: 14 ÷ 11 = 1. 2727 x *

*1.272797403131*

*…x 3555.*

__555__= 5759.729662…The 3555.__555__x 9 = 32000,*to increase the accuracy we employ the yards in one modern-day mile: 1760 in addition to the Greek mile {5068.8} reduced to 506.88*

*Initially **2.049 1818*

*x 1760 = 3606.56 that minus 3024 =*

*582.56*

*that minus*

*506.88*

*= 75.68 that multiplied by 120 = 9081.6 this minus 9072 = 9.6*

*subsequently*

**√2**x**√Pi**÷**Phi**÷ 2.049__18__18 = 0.7560000079729…x 12000 = 9072.0000956753…÷ 1.575 = 5760.00006074…*Two options of many:*

*One:*

*The **2.049 1818*

*minus the Egyptian cubit of 1.7*

__18__18 = 0.331 exactly*This 0.331 x 24000 = 7944 this multiplied by the Schooldays Pi {22 ÷ 7} of 3.*

__142857__= 24966.__857142__that minus the NC Earth mean of 24883.2 = 83.6__571428__one seventh of 585.6 this resembles the prior 582.56*hence 585.6 minus*

*582.56*

*= 3.04, this multiplied by 2000 = 6080 the Sea mile*

*Two:*

*The **2.049 1818*

*minus the Egyptian foot of 1.1*

__45__45 = 0.903__72__72 that multiplied by 5280 = 4771.68, this minus one tenth of a Greek mile: 506.88 = 4264.8 that multiplied by 5.__81__81 {64 ÷ 11} obtains an Earth Intermediate circumference of 24813.3__81__81 otherwise add this to the*2.049*

__18__18*to obtain exactly 24815.431*

*North **to South: **2976.278125** **feet is **1732.22536 375661 *

*Egyptian cubits of 1.7*

__18__18,*East **to West: **2435.778125** **feet is **1417.64864 417989*

*Egyptian cubits of 1.7*

__18__18*Speed of Light in a vacuum: 299792458 metres per second*

*Hence: 1 ÷ 0.3048 x 299792458 ÷ 5280 = **186282.3970512208701…*

*{A} **1732.22536 375661*

*is the square root of*

*3000604.71084173…*

*{B} **1417.64864 417989*

*is the square root of*

*2009727.6783450922…*

*{C} **2009727.6783450922**… added to **the 3000604.71084173**… = **5010332.38918682506…*

**{D}** the NC {**N**umerical **C**anon} Earth to Sun distance is: 93312000 {miles} *Subsequently 93312000 ÷ **5010332.38918682506…** = **18.623914094279…*

**{E}** this *18.623914094279…**plus **0.0043256108429** = 18.62823970512…x 10000 = **186282.3970512208**…this is the Speed of Light correct to 10 decimal places, there are Machiavellian methods to verify the **exact 0.0043256108429; nonetheless we employ the GP Apothem etc **Accordingly without the need to scam, we can obtain 37 ÷ 14 = **2.6 428571*

*the GP Apothem is the √373284 = 610.9697210173…that divided by 2.6*

__428571__= 231.177732276…*Subsequently 1 ÷ 231.177732276… = 0.004325676137… this added to the *

*18.623914094279…*

*obtains 18.62823977041…that multiplied by 10000 =*

*186282.3977041*

*… the Speed of Light correct to a mere*

**3**decimal places*Accordingly all that needs be is to “modify” the NC Earth to Sun distance: 93312000, subsequently maintain it to be exact, given that the Sun Waxes and Wanes, there is no clear-cut distance at any one time, nonetheless why deceive whilst “in close proximity to” figures are at hand?*

*Re {A} and {B}*

*The GP: 1881 { 19 x 99} the Sea mile: 6080, a *

*Comma of Pythagoras*

*{531441:524288} component, namely: 524288, the Schooldays Pi {22 ÷ 7} of 3.*

__142857__, the*Rhind Papyrus*

*{256:81} of*

*3.*

__160493827__**{A1}** the **{A}**: *1732.22536 3756613*

*…x 1881 ÷ 6080 x 524288 ÷ 3.*

__142857__÷*3.*

__160493827__*= 28286547.3 that divided by the North to South:*

*2976.278125*

*feet will obtain*

*9504*

*which, for example, is 1.8 miles of 5280*

*{B1}** The** {B} **1417.64864 417989*

*x 1881 ÷ 6080 x 524288 ÷ 3.*

__142857__÷*3.*

__160493827__*= 23149635.3 that divided by the East to West:*

*2435.778125*

*feet will obtain*

*9504*

*which, for example, is 11 x 864*

*There is speculation the Three Giza pyramids are enclosed in a rectangle that embraces the √3 the √2 and more besides, there being no watertight rationale why this should not be the case as will be observed within the following. All the numbers employed relate to the Great Pyramid which I consider to be the focal point of the entire Giza complex*

*A few methods to follow:*

*North** to South: **2976.278125** **feet*

*Actual Pi x 0.61602671118…x 2976.278125 = 5760.0059077…tolerable as 5760 the GP {Great Pyramid} height, this 5760.0059077...divided by 1.904761 = 3024.003101573... tolerable as 3024, the GP base perimeter *

*The employed 0.61602671118…x 199.*

__666__=**123**, the 199.__666__x 3 = 599, one shy of 600, the 1.__904761__x**567**=**1080**, the lunar, Yin-Yang number*The GP height of 5760 reduced to 576 ÷ 567 = 1.015873 which is the Eye of Horus fraction {63:64} in reverse as it were In view of the fact that 63 ÷ 64 = 0.984375, in that case 1 ÷ 0.984375 = 1.015873 *

*The GP Tan is 480 ÷ 378 = 1.*

__269841__that multiplied by the 0.984375 = 1.25, the 1.__904761__x 1.6__592__592 = 3.__160493827__which is the Rhind Papyrus {256:81}*Due to the cyclic 592, the 1.6 592592 multiplied by the Platonic Year of 25920 = 43008 that divided by the 567 = 75.851851 that multiplied by the lunar, Yin-Yang number: 1080 = 81920, the thirty-third PWS {Plato’s World Series} member is 8192*

*The 1. 904761 multiplied by 0.5530864197… will obtain the FP {musical scale: Pythagorean Limma {256:243} the 0.5530864197…x 14811.428571 = 8192 as indicated prior, the end PWS member is 10368 In that case 10368 ÷ 14811.428571 = 0.7, the 1.904761 x 0.7 = 1.333 one third of 4, likewise the 75.851851, is 64 x 1.185185, which is the musical scale: Pythagorean Minor Third {32:27}*

*The East to West : *

*2435.778125*

*feet divided by*

**√2**= 1722.3552296… this is the square root of 2966507.5371142578125 this is 1000000 x*2.9665075371142578125*

*Hence North to South: **2976.278125** feet multiplied by **2.9665075371142578125** x **2976.278125 **= 8829.1514903607911529541015625 this divided by √3 = 5097.5129896757…This 5097.51298967…÷ 2435.778125 x *

*3787.*

__87__87*x*

**Pi***= 24903.853969… a tolerable Earth Equatorial circumference.*

*The GP {*

**1st**Pyramid} base perimeter of 3024 ÷*3787.*

__87__87*=*

*0.798336,*

*this will obtain numerous ancient and modern-day units of measure. It is easier to indicate that 479001600 {=12!} divided by 0.798336 = 600000000*

*T**hen again the North to South: **2976.278125** feet divided by √3 = 1718.3549766519… this is akin to 1000 Egyptian cubits of 1.71818*

*consequently 1718.3549766519… ÷ 1000 = 1.7183549766519…this multiplied by 440 = 756.07618972… x 4 = 3024.304758907…*

* **The GP height of 5760 ÷ 3024 = **1. 904761*

*as indicated prior*

*Hence the **3024.304758907**… x **1. 904761*

*= 5760.580493156… this is 12 x 480.048374…tolerable as 480 the GP height {*

**1st**Pyramid}*Hence the*

**√3**x 1000 x 1.7__18__18 = 2975.97820573… a difference of North to South:*2976.278125*

*feet minus 2975.97820573… = 0.2999192680199…*

*Accordingly √2 x √3 x 1000 = *

*2966.5075371142578125*

*Therefore a difference of: 2976.278125 feet minus 2966.5075371142578125 = 9.7705878857421875*

*Then again **2966.5075371142578125** divided by my calculated East to West **2435.778125** feet = **1.2178890625** Subsequently the 9.7705878857421875 ÷ 1.2178890625 x 120 x Pi = 3024.433807…slightly more than the GP base perimeter of 3024, nevertheless allowable I would assume in view of the fact that actual Pi is employed*

*The GP height of 5760 x 6.8 x 153 = 5992704,*

*this 5992704 ÷ 1110.1 ÷*

**Pi**= 1718.34693106309…*The North to South:*

*2976.278125*

*÷*

*1718.34693106309*

*… = 1.732058…whereas the*

**√3**is 1.732050807…*The*

*1110.1*

*x*

*307800*

*=*

*341688780*

*this is exactly*

*56198.8125*

*Sea miles of 6080*

*The **341688780 **is **17983620* *x 19, which is Gem: Eve, 19 is a prime number, 19 also related to the Metonic cycle*

*The Maya temples 4 sides comprised of 91 steps hence 91 x 4 = 364 plus the actual top platform:*

**1**=**365 ,**this is Gem {Gematria Value} Abraxas, Mithras, the employed 307800 is exactly 50.625 Sea miles of 6080*The 50.625 x 256 = 12960**, the 17983620 is 12960 x 1387.625 that multiplied by the 256 = 355232 which is 320 x 1110.1 the 1387.625 x 40.5 = 56198.8125. The 56198.8125 x 256 = 14386896 which is the GP { 1st Pyramid} base perimeter of 3024 x 4757.571428 one seventh of 33303 which is the 1110.1 x 30*

*Likewise **7.2 555*

*multiplied by the prior*

**153**{Gem: the “fishes“} will regain the*1110.1*

*Hence the*

*33303*

*÷*

*7.2*

__555__*= 4590*

*the 4590 divided by Gem: Divine Circle:*

**1224**= 3.75 Otherwise 4590 ÷ 5280 x 1408 =**1224**, whereas**12.24**x 0.25__66660__= 3.14159265…hence**Pi**correct to**8**decimal places the 0.25__66660__x 9.9999 = 2.566635*The **1408 **x 2.25 = 3168 Gem: Lord Jesus Christ, then again 3168 is 0.6 miles of 5280, the *

*1408*

*x 3.6 = 5068.8 the Greek mile, the*

*1408*

*x 0.45 = 633.6 the Greek furlong,*

*the 1408 divided by the longer value Greek foot of 1.01376 = 1388.*

__888__that multiplied by 72 = 100000*With reference to:*

*“This 5992704 ÷ *

*1110.1*

*÷*

*Pi**=*

*1718.34693106309…*

*The **1718.34693106309**… resembles an increased Egyptian cubit 1.7 1818 of which there are 440 in the GP base side length since 756 ÷ 440 = 1.71818*

*consequently a reduced 1.71834693106309… x 440 = 756.07264966776…The GP height is 5760 {480 x 12} moreover 5760 is 756 x 7.*

__619047__*Hence the **756.07264966776**… x **7. 619047*

*= 5760.55352127…this divided by 12 = 480.0461267731…this is*

*1.71834693106309*

*… x 279.365079 that multiplied by 1.575 = 440*

*, the 1.575 is 756 ÷ 480*

*Accordingly it could be assumed the actual Egyptian unit employed within the GP is the Pi concerned: *

*1.71834693106309…*

*With regard to the*

*7.*

__619047__*this divided by*

*2.410*

__714285__*= 3.*

__160493827__which is the “Rhind: Pi” as indicated upon the*Rhind Mathematical Papyrus*

*by the Egyptian scribe:*

**Ahmes**circa: 1650: BCE*However the “Rhind” is three times the musical scale:Pythagorean Limma {256:243}*

*We basically go round in proverbial circles, riding the numerical carousel*

*Since the **2.410 714285*

*x 448 =*

**1080**the lunar, Yin-Yang number, the 448 x 1.6875 = 756, furthermore the 1.6875 x 640 =**1080***therefore 2.410*

__714285__plus 0.732__142857__= 3.__142857__the Schooldays Pi {22 ÷ 7} the 0.732__142857__x 7 = 5.12 Otherwise 2.410__714285__minus 0.696__428571__= 1.__714285__another version concerning an Egyptian cubit {12 ÷ 7} the 4th PWS member is 512*The **0.696 428571*

*x 448 =*

*312*

*this is the*

*Maya*

*Third Sun hence*

*0.696*

__428571__*is implicated via the*

*Maya*

*Calendar.*

*Likewise: 0.696*

__428571__x 37.__333__=**26**Gem: YHWH furthermore**26**x 12 = 312, otherwise**26**x 62.5 =**1625**Gem: Tree of Life The 37.__333__x 20.25 = 756*Whilst*

*2.410*

__714285__*will, as indicated prior, obtain*

**1080**likewise it obtains: 216, 432, 1296, 1512, 1728, 1944, 2592, 3024, 237600, 93312000, and 479001600 {=12!} etc*As prior: “Otherwise 4590 ÷ 5280 x **1408 **= 1224”*

*This time brief as feasible, given that again the interconnections are numerous*

*The East to West **2435.778125** **÷ **1722.355 222*

*= 1.4142135684… whereas the*

**√2**is 1.4142135623…*The*

*1722.355*

__222__*x 3.*

__142857__x 3024 {GP base perimeter} obtains: 16369264.032, that divided by the prior*1408*

*=*

*11625.89775 that multiplied by*

*Pi**x 0.6*

__81__81 {15 ÷ 22} obtains an Earth Equatorial circumference of 24902.6147473… miles*Conversely: **The Earth “tilt” is approximately 23.5 degrees likewise 90 {degrees} minus a reduced and most appropriate, Gem: Weapons of god {665} of 66.5 = 23.5 *

*The modern-day mile of 5280 ÷ 3200 =*

*1.65*

*The GP Tan is 480 ÷ 378 = 1.*

__269841__this is the square root of 1.61249685059208…Subsequently**23.5**÷ 1.65 =**14.**t__24__24*his divided by 7 then multiplied by 1.61249685059208…= 3.2808377479… a “near miss” feet-metres ratio, in view of the fact that the actual is: 1 ÷ 0.3048 = 3.2808398…*

*In that case 7 ÷ √3 x √2 = 5.71547606649408… that multiplied by the “near miss” *

*3.2808377479*

*…= 18.7515496265038… the*

**Log**of this is: 1.2730371636067…this multiplied by*1360.*

__56__56*=*

*1732.0506443…*

*Whereas*

**√3**x 1000 = 1732.050807568…in the vicinity of the*1732.0506443…*

*Whereas the accurate: 1 ÷ 0.3048 x 5.71547606649408…= 18.7515618979464… Log of this is: *

*1.2730374478188*

*…this*

*multiplied by the prior*

*1360.*

__56__56*=*

*1732.05103102…*

*Whereas the*

**√3**x 1000 = 1732.050807568…in the vicinity of*1732.05103102*

*The employed*

*1360.*

__56__56*x 99 =*

*134696 t*

*his*

*multiplied by the*

**14.**= 1918397.__24__24__57__57 this multiplied by the “Land” mile of 5280 = 10129139200*This 10129139200 divided by the **1360. 5656*

*= 7444800 which divided by the “Sea” mile of 6080 = 1224.47368421052… that multiplied by 1881 {99 x*

**19**} obtains 2303235 which is the Earth “tilt”

*23.5**x*

*98010 t*

*his*

*is 90 x 1089 which is one ninth of 9801 hence a reversed 1089*

*Or else **98010** is the mile of 5280 x **18.5625** that multiplied by the FP {**Pythagorean Limma** **{256:243} obtains 19. 555 which is one ninetieth of 1760 the yards in one mile *

*Or*

*98010*

*is the*

*Platonic*

*year of 25920 x 3.78125 the above*

*18.5625*

*divided by this 3.78125 = 4.*

__90__90 that multiplied by 1.1 = 5.4*Or 98010 is the seconds in 24 hours: 86400 x 1.134375 **Or **98010 **is the cubic inches in one cubic yard: 46656 x 2.10069 444 that multiplied by the 18th PWS member: 2304 = *

*4840*

*this is the amount of square yards in one acre*

*Or **98010** is the square feet in one acre: 43560 x 2.25 this 2.25 divided by the **1.134375** = **1.9834710743801652…** and this multiplied by **96.8** = 192 Gem: Mary in addition to the 1st PWS member 384 is twice 192*

*the employed 96.8 x 50 = 4840 as we observe above*

*Hence **1.9834710743801652...** .will obtain 384, 432, 486, 576, 768, 1296, 2916, 6144, 6336, 9216 etc** In other words 479001600 {=12!} divided by the 1.9834710743801652…= 241496640 which divided by the 98010 = 2464 this **divided by the GP base perimeter of 3024 = 0. 814814 this multiplied by a *

*Pythagorean Limma*

*{256:243} component, namely 243 = 198*

*this 198 obtains: 3168, 3960, 6336, 7920, 43560, 237600, 11404800, 479001600 {=12!}*

*As a further example the **479001600 **÷ 198 = 2419200 this relates to Hebrew feet and the Roman cubit **1.4598144** Via reference to the **Earths distance from its centre** otherwise, as mentioned via John Michell within “The Dimensions of Paradise”*

*{Quote} **“**The shortest from the centre of the earth to its surface**” **{Unquote}*

*Given that **1.4598144 **x 100000000 = 145981440 this is 7 x 20854491. 428571 this multiplied by 2 x Pi 5280 = 24816.78676755… the Earth Intermediate circumference, in view of the fact that it is 2 x Pi x 3949.714285 which is approximately: “Earths distance from its centre” at the Poles*

*Or **20854491. 428571*

*x 2 x 3.*

__142857__÷ 5280 =*24826.775510204*

*…approximately 10 miles over the*

*24816.78676755*

*The **20854491. 428571*

*÷ 2419200 =*

*8.62040816326*

*… this multiplied by 2880 =*

*24826.775510204…*

*The **20854491. 428571*

*÷*

*1.4598144*

*= 14285714.*

__285714__one seventh of exactly 100000000*However the Earth of*

*24826.775510204*

*… multiplied by Gem: Founder of the City:*

**1225**= 30412800 which, for example, is 50000 Roman furlongs of 608.256*The 8.62040816326… multiplied by Gem: Founder of the City*

**1225**= 10560 obviously 2 miles of 5280*The **20854491. 428571*

*divided by the ancient ratio of measure: {176:175} of 1.00*

__571428__= 20736000 which is the end PWS member: 10368 x 2000 hence*I employed Gem: Founder of the City:*

**1225**given that I typically “locate” the ratio of measure: {176:175} of 1.00__571428__via dividing*1239.04*

*by*

**1225**obtaining: 1.01146**1224**48979… the square root of this is: 1.00__571428__furthermore we “see” in the neighbourhood of**1225**within the 1.01146**1224**48979…*The GP volume of 91445760 divided by the Earth of **20854491. 428571*

*= 4.384943*

__18__18 this divided by the Egyptian cubit of 1.7__18__18 = 2.55208__333__moreover this multiplied by the GP height of 480 =**1225***The above*

*1239.04*

*divided by the Roman furlong of 608.256 = 2.*

__037__037 that multiplied by the 23rd PWS member: 3888 = 7920* This 7920 x 3. 142857 = 24891.428571 that minus the NC Earth mean circumference of 24883.2 = 8.2285714 this multiplied by 700 = 5760, the GP height {480 x 12} This Earth of 24891.428571 minus the prior observed Earth of 24826.775510204…= 64.6530612244897959… that multiplied by Gem: Founder of the City: 1225 = 79200*

*The Sea mile of 6080*

*The options are numerous, given that whilst we employ the square roots of 2…3…etc, the Sea mile of 6080, with 1881, which is the sloping floor-line length of the magnificent Grand Gallery, the following crops up *

**√3**÷ 2 x 6080 ÷ 1881 =*2.79927403243…*

*The North to South **2976.278125** ÷ **2.79927403243**…= **1063.232141803**… this multiplied by the √3 = 1841.57208984375 *

*In that case*

*2976.278125*

*÷ 1841.57208984375 = 1.*

__61__61 this is one half of*3.*

__23__23*{6080 ÷ 1881} The*

*1063.232141803*

*… x*

*3.732365376*

*…=*

*3968.3708*

__333__*this divided by the FP {256:243} will obtain 3766.852001953125 that divided by*

*1381.1790673828125*

*= 2.*

__72__72 which is one eleventh of**30***The **3.732365376**… divided by the √3 = *

*2.154882*

*this multiplied by*

*1381.1790673828125*

*will regain the North to South*

*2976.278125*

*The 2.154882 multiplied by the Roman cubit of 1.4598144 = 3.145728 t*

*his*

*possibly will gel with the Schooldays Pi of 3.*

__142857__in view of the fact that the cyclic digits__142857__are but rearranged as it were, however we follow a different route*The 3.145728 divided by the below: 0. 888 = 3.538944 that divided by the longer value Greek foot of 1.01376 = 3.49090 which is one eleventh of 38.4, hence 3.49090 will obtain: 768, 1152, 1536, 2304, 3072, 3456…10368, 25920, 86400 etc*

*And the prior **3968.3708 333*

*divided by the employed*

*1381.1790673828125*

*= 2.873176206509539842 this multiplied by 1881 subsequently divided by the Sea mile of 6080 =*

*0.*

__888__*which is one ninth of*

**8***In addition to 8 divided by the 2.154882 = 3.7125 that multiplied by 1422.*

__222__= 5280, the modern-day mile*The square root of the **Comma **{531441:524288} component, namely 531441 is 729, the 1422. 222 x 729 = 1036800, the last PWS member is 10368 The *

*3968.3708*

__333__*divided by this 1422.*

__222__= 2.7902607421875 that multiplied by*1066.*

__666__*will regain the*

*2976.278125*

*The North to South*

*This 1066.*

__666__is one third of 3200*√2 x Phi = 2.2882456112707…*

*√3 ÷ **2.2882456112707**… x 4000 = **3027.735832…*

*Subsequently 81.1 ÷ 81 = 1.0 012345679*

*the 3027.735832…÷ 1.0*

__012345679__= 3024.0024958…that multiplied by 1.__904761__= 5760.004754007…*The 2.2882456112707… ÷ √3 x Pi x 6000 = 24902.5106096… a tolerable Earth Equatorial circumference This 24902.5106096… multiplied by 5280 afterwards divided by 360000 = 365.236822274… admittedly a somewhat shabby Earth year, nonetheless in the neighbourhood of *

*Whereas 1. 666 x Pi x Pi x 2000 ÷ 2.2882456112707… x √3 = 24902.129079… a tolerable Earth Equatorial circumference that multiplied by 5280 afterwards divided by 360000 = 365.2312265004…another somewhat shabby Earth year, the 1.666 is one third of 5*

*Giza Rectangle resumed*

*North** to South: **2976.278125** feet*

*East** to West: **2435.778125** feet*

*Hence we obtain a “rectangle” of area: **2976.278125** x **2435.778125** = **7249553.150791015625*

*As we presently observe “Hence {A} x {B} ÷ {C} = **24913.151693204042**”*

*The **7249553.150791015625** multiplied by √2 x *

*Pi**x*

*Phi**then divided by the*

*24913.151693204042*

*…x*

*4.3*

__36__36*= 9071.117041719… again tolerable as the*

**1st**{Great Pyramid} base side length of 9072*The employed*

*4.3*

__36__36*x 5280 = 22896 that divided by the*

**1st**Pyramid height of 5760 = 3.975 this divided by the**1st**Pyramid ratio 1.575 = 2.__523809__*this divided by the Rhind Papyrus {256:81} of 3.*

__160493827__subsequently divided by the Schooldays Pi {22 ÷ 7} of 3.__142857__= 0.2540838068181*Merely to be brief since there are options aplenty: **0.2540838068181** x **17.0 666*

*=*

*4.3*

__36__36*as we observe prior, the 17.0*

__666__x 531.5625 = 9072 the 531.5625 x 2560 = 1360800, the Maya association: 1366560 minus the GP 5760 = 1360800 the 17.0__666__x 337.5 = 5760…the 337.5 x 4032 = 1360800*Acres of space*

*North to South: **2976.278125** feet*

*East to West: **2435.778125 **feet*

*Seeing as there are **43560 **square feet in one acre, in that case the “rectangle” of area: **2976.278125** x **2435.778125** = **7249553.150791015625** that divided by **43560** = **166.426840008976483 5858 *

*this multiplied by*

**53533.**__333__*= 89093835.01813874…*

*The *

*Comma of Pythagoras*

*{531441:524288} component, namely 524288 x*

*166.426840008976483*

__58__58*=*

*87255595.094*

__62__62*this divided by the area of*

*7249553.150791015625*

*=*

**12.035996326905417**…*The **87255595.094 6262*

*multiplied by*

**√3**then divided by the

*12.035996326905417**…÷*

*7249553.150791015625*

*= 1.7320508075688772…obviously*

**√3***Otherwise **7249553.150791015625** x 3 = 21748659.452373046875 this multiplied by *

*12.035996326905417*

**…**= 261766785.283__87__87 which is**3**x*87255595.094*

__62__62*The 261766785.283 8787 divided by the *

*166.426840008976483*

__58__58*= 1572864 which is*

**3**x 524288*However the*

**12.035996326905417**…x 2.527141571044921875 = 30.41__666__*The*

*2.527141571044921875*

*multiplied by the*

*Comma*

*component: 524288 = 1324950 which is the mile of 5280 x 250.9375 that multiplied by*

*213.*

__333__*regains the*

*53533.*__333__

*Furthermore the employed 213. 333 x 3 = 640, acres in one square mile *

*The*

*53533.*__333__*x*

**3**= 160600 which is*30.41*

__666__*miles of 5280*

*The*

*30.41*

__666__*x 48 = 1460 the Sothic cycle*

*The*

*30.41*

__666__*x*

**19.2**= 584 the Maya Synodic period of Venus*The*

*30.41*

__666__*x 12 =*

**365**Gem: Abraxas, Mithras or t*he*

*30.41*

__666__*x 72 =*

**2190**Gem: Son of man*Or t**he **30.41 666*

*x*

*9830.4*

*=*

*299008*

*Then 1881 x 6080 x 30 ÷*

*299008*

*÷*

*Pi**= 365.2421989187… a tolerable Earth year that multiplied by 360000 ÷ 5280 = 24902.8771990053… a tolerable Earth Equatorial circumference*

*The **9830.4** ÷ 9072 = **1.0835978** that multiplied by the GP 5760 = 6241. 523809 this divided by the *

*Rhind Papyrus*

*{256:81} of 3.*

__160493827__=*1974.*

__857142__*that divided by the Schooldays Pi {22:7} of 3.*

__142857__= 628.__36__36 which is one eleventh of 6912, the Egyptian Stade is 691.2, and the 31st PWS member is 6912*Otherwise the 1974.*

__857142__x 7 = 13824 which is 2 x 6912 etc*Then again the Radians with regard to: 3. 142857 is *

*0.44897959*

**1836**7346*… that multiplied by Gem: Founder of the City:*

**1225**= 550*The above 1.0835978 ÷ 0.44897959*

**1836**7346… = 2.413468, this divided by a reversed Eye of Horus fraction {64:63} of 1.__015873__= 2.37575 this multiplied by the Grand Gallery {sloping} floor line length of 1881 = 4468.8 that divided by the Sea mile of 6080 = 0.735*This **0.735** x 12342. 857142 = 9072, the 12342.857142 x 7 = 86400*

*And 0.735 x 7836.73469387755102…= 5760, the 7836.73469387755102… x*

**49**= 384000*{the*

**1836**is 1.5 x**1224**}*As we observe prior: “The **30.41 666*

*x*

*9830.4*

*=*

*299008*

*”*

*The 9830.4 ÷ 0.735 divided by the “Rhind” of 3.*

__160493827__then multiplied by Gem: Founder of the City:**1225**= 5184000, the 27th PWS member is 5184*Giza Rectangle yet again*

*North to South: **2976.278125** feet*

*East to West: **2435.778125** feet*

*Hence: **2976.278125** x **2976.278125** = **8858231.477353515625*

*Hence: **2435.778125** x **2435.778125** = **5933015.074228515625*

*Then **8858231.477353515625** + **5933015.074228515625** = 14791246.55158203125 the square root of this is **3845.93896878018999**… obviously the diagonal length **Whereas the √3 x *

*1292.327*

__666__*x 1.7*

__18__18 =*3845.938970664463*

*…therefore tolerably in the neighbourhood of*

*3845.93896878018999*

*…*

*Subsequently via slight alterations to the Pyramid’s base side length’s we will obtain a multiple of the √3, nevertheless we continue with our produced *

*3845.93896878018999…*

*We observed prior {one example} “The **30.41 666*

*x 48 = 1460 the Sothic cycle”*

*“The ***53533. 333**

*x 3 = 160600 exactly which is*

*30.41*

__666__*miles of 5280”*

*The above employed **1292.327 666*

*÷*

*30.41*

__666__*=*

*42.487484931506*

*this multiplied by the 160600 = 6823490.08, this obviously divided by*

*127.4624*

__54794520__*=*

*53533.*__333__*In view of the fact that the:*

*127.4624*

__54794520__*is 3 x*

*42.487484931506*

*…*

*Likewise prior we observe:*

*“Hence {A} x {B} ÷ {C} = **24913.151693204042**…”*

*The **24913.151693204042…**÷ **3845.938968780189**…afterwards multiplied by 1400.48 = 9072.0032133958… yet again tolerable as 9072 the 1st Pyramid base side length and 9072.0032133958 ÷ 1.575 = 5760.0020402513…likewise tolerable as 5760 the 1st Pyramid height {480 x 12}*

*Now we employ Pi and Phi*

*Pi** ÷ **Phi **= **1.9416110387254**…then: **Pi** ÷ **Phi **÷ **Phi** = **1.199981614864…*

*With reference to The Giza area: **8858231.477353515625** + **5933015.074228515625** = 14791246.55158203125 the square root of this is **3845.9389687801**… that divided by the **1.9416110387254**…= 1980.79784883…t**his multiplied by 4 x 3.142857 = *

*24901.458671058*

*… a tolerable Earth Equatorial circumference.*

*The NC Earth to Sun mean distance: 93312000 ÷ 3845.9389687801…÷ 1.199981614864 ÷ 24901.458671058…= 0.811962047053…*

*In that case 6.4 ÷ 3 x *

*0.811962047053*

*= 1.73218570038…Whereas the*

**√3**= 1.732050807568…Bearing in mind as we employ actual

**Pi***in the company of actual*

*Phi**,**the products are especially reasonable*

*The NASA mean Earth to Sun distance: 92955820 divided by the *

*3845.9389687801*

*… ÷*

*1.199981614864*

*…÷*

*24901.458671058*

*…=*

*0.808862717471…t*

*his multiplied by*

*3738.5825*

*= 3024.0000004428…tolerable as the*

**1st**pyramid base perimeter of 3024 {9072 ÷ 3}*the 3024.0000004428…x 1.*

__904761__= 5760.000000843…this is 12 x 480.00000007029…tolerable as the**1st**pyramid height*The **1. 904761*

*x 567 =*

**1080**the lunar, Yin-Yang number in addition to**1080**x 2.8 = 3024,*the*

**1080**x 5.__333__= 5760, hence the 5.__333__x 567 = 3024 The exact 3738.5825 x 6.660__54__54 = 24900.998676__81__81 a tolerable Earth Equatorial circumference*The employed 6.660 5454 divided by the Egyptian foot of 1.14545 = 5.81476190 this multiplied by 567 = 3296.97 which is the 1080 x 3.05275 t*

*his*

*divided by the*

*6.660*

__54__54*= 0.458*

__333__one third of 1.375 that multiplied by 3840 = 5280 {1st PWS member is 384}*The NC {***N**umerical **C**anon} Moon

*The NC Moon diameter of 11404800 reduced to 1140.48 plus 260 = 1400.48** the 260 multiplied by Maya Tzolkins: 5256 = 1366560, this is the Maya super number the 26th member of PWS is 4608 **The 1360800 days: **Mayan **Long Count {9.9.0.0.0} divided by 46080 = 29.53125 that multiplied by 12.8 = 378 {half of 756}*

*The: 1360800 days indicating 400 Saturn and 378 Jupiter Synodic orbits, it is also interesting that: 1360800 ÷ 400 = 3402 which is 9 x 378 the 1st Pyramid base side length of 9072 ÷ 3402 = 2.666 one third of 8*

*Then again the 1st Pyramid height of 5760 ÷ 3402 = 1.693121 that multiplied by 907.2 = 1536, the 13th PWS member is 1536*

*the 9072 is 24 x 378*

*With reference to the Giza area we observe prior: **“Then 8858231.477353515625 + 5933015.074228515625 = 14791246.55158203125 …”*

*We also observe: “**166.42684000897648358585** this multiplied by **53533. 333*

*=*

*89093835.01813874421*

*…”*

*The **14791246.55158203125** is one twelfth of 177494958.618984375 that multiplied by 378 = 3254074241.348046875 this divided by the above **8909383.501813874421**… = 365.2412359043… a tolerable Earth “year” that multiplied by 360000 afterwards divided by the mile of 5280 = 24902.8115389308…a tolerable Earth Equatorial circumference*

*Until the next essay*

*Derek Skhane Copyright © 2006 All Rights Reserved*